I’m fine with basic rearrangements like turning y = ax + b into x = (y – b)/a. I get confused when the variable I want to make the subject shows up both in the numerator and the denominator, and I’m not sure how to treat steps that involve multiplying or dividing by expressions that might be zero. For example, if I try to make x the subject in y = (ax + b)/(cx + d), I can rearrange to something like x(yc – a) = b – yd. At that point, do I have to split into cases for yc – a = 0, and how do I keep track of the original condition cx + d ≠ 0 while still aiming for an equivalent formula for x?
I hit the same issue with T = L/(1 – rL) when solving for L. Multiplying by (1 – rL) seems to assume it’s nonzero, but that’s also a domain restriction of the original equation. Later I want to divide by something like (1 + Tr). Is there a clean checklist for carrying domain restrictions through these steps so the final formula is genuinely equivalent? A brief outline using either example would help me see the logic.















